I wouldn't stop, I'm no expert or own a helicopter so the fact I'm flying one and not crashing is amazing. Trying to land is probably not going to be fun and I'm not going to try that until I know for fact I am somewhere safe.
This, too.Revnak said:Also, I don't think helicopters usually work that way. I'm pretty certain a helicopter's limiting factor is volume rather than weight when dealing with objects of human density.
Thank you! Thank YOU! Athousand times thank you, you are actually addressing the questions SPIRIT! You may find my distinction between n=1 and n=2 interesting.isometry said:The mathematical answer would be to maximize the expected number of survivors.
Let n be the number of people I choose to pickup. Then the number of survivors if we don't crash is n + 2, and the probability of not crashing is (5-n)/5, so the expected number of survivors S is:
S = (n+2)(5-n)/5
n = 0, S = 2
n = 1, S = 2.4
n = 2, S = 2.4
n = 3, S = 1.2
n = 5, S = 0
So n = 1 or n = 2 would both be logical courses of action with equivalent expected outcome on average.
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Utilitarianism for life!Nouw said:I was reading Justice:What's the Right Thing to Do? and it explored the concept of utilitarianism and libertarianism. More in a moral sense of course. I'm wondering what they would do here. Would the former work out a math equation to see how many lives they could save? Would the latter flip a coin or pick at random? Hmm...
Personally, I'd either get all of them with the mindset that I leave no-one behind or take 3. It becomes easier if one volunteers to stay behind.