it does rely quite heavily on people not being able to spot that 25 is non-divisible by 3Lizmichi said:
Clicks and Giggles: Riddle Me This
- Thread starter Spinwhiz
- Start date
Yep. Specifically, one of the earlier levels where GLaDOS lies about not monitoring the test chamber.voldemort101 said:
Alright here's one:
You have 11 identical marbles and a 12th that is of a different weight than the rest (could be either lighter or heavier). You have a balance scale which you can use no more than 3 times to determine which of the 12 marbles is the odd one out.
Remember, the odd marble out can be either heavier or lighter than the rest, and you must use the scale to figure it out.
You have 11 identical marbles and a 12th that is of a different weight than the rest (could be either lighter or heavier). You have a balance scale which you can use no more than 3 times to determine which of the 12 marbles is the odd one out.
Remember, the odd marble out can be either heavier or lighter than the rest, and you must use the scale to figure it out.
Hey guys. Been following this thread for a few weeks and thought I'd try my hand at one of the solutions:
Divide the 12 marbles into four groups of 3 (i.e. Groups 1, 2, 3, and 4)
Take two of the groups of 3 (e.g. 1 and 2) and weigh them against each other
Replace one of the groups (2) with another (3)
-- If 1 and 2 weighed equally, but 1 and 3 did not, then Group 3 contains the "odd" marble
-- If 1 and 2 did not weigh equally, but 1 and 3 did, then Group 2 " "
-- If 1 and 2 did not weigh equally, and 1 and 3 did not weigh equally, then Group 1 " "
-- If 1, 2 and 3 all weighed equally, then Group 4 " "
Take two marbles from whichever group contains the "odd" marble and weigh them against each other
-- If they weigh equally, the third marble is the "odd" marble
-- If they do not weigh equally, ????
And with that, I'm going to go ahead and call this one impossible. Any way I can figure it, you need at least 4 weighings to be able to conclusively get the answer. But feel free to either springboard off this or show me a better way, because now I'm really curious
EDIT: Just looked up the answer and though I'd weigh in (pun intended): the answer I found (which I'll link to) is a good bit more complicated than what I came up with, but definitely possible; props to Tilted_Logic on a real brain-cruncher
Divide the 12 marbles into four groups of 3 (i.e. Groups 1, 2, 3, and 4)
Take two of the groups of 3 (e.g. 1 and 2) and weigh them against each other
Replace one of the groups (2) with another (3)
-- If 1 and 2 weighed equally, but 1 and 3 did not, then Group 3 contains the "odd" marble
-- If 1 and 2 did not weigh equally, but 1 and 3 did, then Group 2 " "
-- If 1 and 2 did not weigh equally, and 1 and 3 did not weigh equally, then Group 1 " "
-- If 1, 2 and 3 all weighed equally, then Group 4 " "
Take two marbles from whichever group contains the "odd" marble and weigh them against each other
-- If they weigh equally, the third marble is the "odd" marble
-- If they do not weigh equally, ????
And with that, I'm going to go ahead and call this one impossible. Any way I can figure it, you need at least 4 weighings to be able to conclusively get the answer. But feel free to either springboard off this or show me a better way, because now I'm really curious
EDIT: Just looked up the answer and though I'd weigh in (pun intended): the answer I found (which I'll link to) is a good bit more complicated than what I came up with, but definitely possible; props to Tilted_Logic on a real brain-cruncher
http://www.numericana.com/answer/weighing.htm#weighing
Sorry for the slow reply. Very good attempt darkapothem2000, I definitely had some real trouble with the marble conundrum when I first came across it too; I love how the order of solving it changes depending on your luck during the weighing.
If no one else wants to give it a shot then the torch can be passed on to someone else.darkapothem2000 said:
At the risk of violating decorum (since I didn't actually get it right), I'll go ahead and share one:
I live in a room with no walls or windows and only one exit
No guards or shackles, only a single chain
I've spent my entire life in this prison; yet when my time is done and I am released, I will not have lost a single day of my life
Who am I?
I live in a room with no walls or windows and only one exit
No guards or shackles, only a single chain
I've spent my entire life in this prison; yet when my time is done and I am released, I will not have lost a single day of my life
Who am I?
I think Spoon got it. Though I'd say a pocket watch to be more specific.darkapothem2000 said:
EDIT: The above was meant to be an elaboration on Spoon's response, and not a response of my own. But just in case it counts as a second attempt, I'll put my guess in a spoiler warning
An unborn child?