DnD Math

[Seydaman]

So I'm sitting here playing Nwn2, and I'm wondering something
What's the chance that when you roll 2 1d20's the first will be a 1, and the second will be 15 or greater?

Essentially: 1d20 + 14 < 1d20 | What is the percent chance of that occuring?

 

[SckizoBoy]

You've asked two distinct questions there.

The first one is 3/10.

The second on is 21/400...

*watch this space*

EDIT: My bad... 21/200 (based on two equal d20 irrespective of when they are rolled)

EDIT2: Bugger, didn't read the question properly: first one is 3/200

And further to first edit, if the d20 of the '1d20 + 14' side of the expression is rolled first, then the probability is 3/80 (based on absolute fulfilment of the condition that 1d20 + 14 < 1d20)

 

[Harkonnen64]

1.5%

1/20 X 6/20 = 6/400 = 1.5/100

If I understood your question right, I believe this is the right answer.