Poll: A little math problem

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FrcknFrckn

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Cheeze_Pavilion post=18.73797.838450 said:
FrcknFrckn post=18.73797.838415 said:
I have two coins, one in each of my hands. I tell you at least one of my hands has a penny in it, and you ask for the coin in the OTHER HAND.
You're changed the question too much. The question states: "What is the probability that the other one is a male?" The reason it tells us something is because it's coming directly from the question-asker, and therefore, gives us a clue as to how to resolve the ambiguity in the rest of the question.
Again, you're missing my point: talking about the 'other one' gives you absolutely no information, whether it comes from me, from you, or from some mystical quantum dog-washer.

And realistically, there is no ambiguity in the question. If you want to generate ambiguity, why not start questioning whether the shop owner is lying in order to make a sale? The thing about word problems is that, unless the question states otherwise, everything is pretty much normal. Why question the method of dog pair selection when the obvious answer is that it's just a random pair of dogs? Occam's razor and all that...
 

FrcknFrckn

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Dammit, why do I keep letting myself get dragged into these so-called discussions? Screw it, I'm going back to lurking and shaking my head quietly at the stupidity of it all...
 

FrcknFrckn

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Cheeze_Pavilion post=18.73797.838548 said:
FrcknFrckn post=18.73797.838507 said:
Why question the method of dog pair selection when the obvious answer is that it's just a random pair of dogs? Occam's razor and all that...
You misunderstand Occam's Razor: it is not that the simplest explanation is the best, it is that in explanations, entities ought not to be multiplied except by necessity.

If ambiguity is found, that necessitates the multiplication of entities. Perfectly consistent with Occam's Razor.

And if you didn't think there was ambiguity in the problem, why were you arguing math with me? We should have been arguing about the whether the ambiguity exists. Otherwise you're doing no better than someone who argues the math of 36 numbers split into red and black to a person who thinks he's looking at a roulette wheel with a green zero on it.
Ambiguity = 0
Probability = 33%

I was arguing math with you in the faint hope that you'd finally 'get it'. But realistically, if after this many pages you still don't get it, you never will. Hence: bye!
 

Alex_P

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Cheeze_Pavilion post=18.73797.838484 said:
Alex_P post=18.73797.838442 said:
FrcknFrckn post=18.73797.838427 said:
Actually, both those cases are 50%. In both, we end up with the same information: Jesus is male. We know nothing about Satan, so there's a 50% chance he's male or female.

The probability difference arises if you ask "Is at least one of them male?" and the answer is "Yes." In that situation, there is only a 33% chance that both Jesus and Satan is male.
No, read the second situation carefully.

The trick is that you're inviting the puppy-washer to decide which dog you're referring to, and he can always pick the more favorable answer. If Jesus were female he could've said "Yes, Satan is male" instead.
If a more favorable answer exists, then there's always one and only one dog that he can refer to--he can't "decide" you're referring to the other dog or "pick" any dog other than the one he picked without lying. If there are equally favorable answers and he can 'decide and pick' well then we're talking about an M/M pair anyways.

C'mon--now you guys are actually talking yourselves out of math that even the 33% people have agreed on for 20+ pages!
Well, this one is intentionally tricky.

First off, to avoid confusion: we're taking it for granted that the puppy-washer only tells you about one of them, okay? So if both are male he won't just shout "both" -- otherwise there's no point since you get perfect knowledge anyway.

Here's the catch:
P(Jesus is male | puppy-washer says "Jesus is male") = 1
BUT!
P(puppy-washer says "Jesus is male" | Jesus is male) < 1
Because if both are male he could have said "Satan is male" instead.

This speaks directly to the problem of referents we had ten pages ago.

Next post will contain the full Bayes-theorem write-up of this.

-- Alex
 

Jumplion

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I find this halarious.

How has this thread not fallen into the dark abyss of the internet already?
 

Faded gamer

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OuroborosChoked post=18.73797.809310 said:
Does it matter what gender the other dog is?
probly not,because no one is going to look down their,and if they do they are really weird.
 

geizr

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Cheeze_Pavilion post=18.73797.838450 said:
FrcknFrckn post=18.73797.838415 said:
I have two coins, one in each of my hands. I tell you at least one of my hands has a penny in it, and you ask for the coin in the OTHER HAND.
You're changed the question too much. The question states: "What is the probability that the other one is a male?" The reason it tells us something is because it's coming directly from the question-asker, and therefore, gives us a clue as to how to resolve the ambiguity in the rest of the question.
No, it doesn't, Cheeze. This is the constant error in your logic. The "other" does not refer to a specific dog because that requires that we know which is the first dog being referenced as male. And don't say that the problem is poorly worded, because it's not. However, your reading comprehension in this case is definitely in question. Let's break down the problem statement line by line.

A shopkeeper says she has two new baby beagles to show you, but she doesn't know whether they're male, female, or a pair. You tell her that you want only a male, and she telephones the fellow who's giving them a bath. "Is at least one a male?" she asks him. "Yes!" she informs you with a smile. What is the probability that the other one is a male?
A shopkeeper says she has two new baby beagles to show you, but she doesn't know whether they're male, female, or a pair.
We are told there are two beagles, but at this point it is unknown whether they are male or female. So, as far as we are concerned, the beagles can be any one of the combinations male/male, female/female, male/female, or female/male.

You tell her that you want only a male, and she telephones the fellow who's giving them a bath.
We have specified that we are only interested in purchasing a male beagle. However, what is more important is the fact there is someone who has access to both beagles simultaneously to be able to examine them for gender. This person examines the beagles while bathing them and obtains their genders.

"Is at least one a male?" she asks him. "Yes!" she informs you with a smile.
This is the first point where your logic falls off, Cheeze. The shopkeeper only asks whether at least one puppy is male, not which one. We don't know at this point if one or both puppies are male. In the case of only one being male, at this point, we don't know which one. We can not force the label on the male one to be dog1. Consider this scenario. The Puppy Washing Man picks up one puppy and looks at it and discovers it is male. At that point, he can truthfully answer the shopkeeper in the affirmative that at least one puppy is male. But, it could be that he picks up the first puppy and discovers it is female. So, he must then pick up and examine the second puppy to properly answer the shopkeeper. It is because we don't know what the Puppy Washing Man had to do to determine if there is at least one male that we get 3 total configurations possible.

What is the probability that the other one is a male?
This is where I think I understand how you are misunderstanding the problem statement, and it's not a matter of the question being poorly worded. We are told that at least one puppy is male. By including that the other one be male to obtain the probability, we are asking for the case that both puppies be male. But we don't know which one to start with to assign as being male. So mentally, we must consider two different scenarios: 1) dog1 is the male and dog2 is the other one, 2) dog2 is the male dog and dog1 is the other one. When you work out the outcomes from both these scenarios, you find there are a total of 3 unique configurations, with the male/male configuration being only 1 of the 3.

Your problem, Cheeze, is that you are constantly misunderstanding "the other one" to reference a specific puppy, and it doesn't. What the statement "the other one" is intended to do is to specify that we want both puppies to be male. It can not specify a specific puppy because we don't have a reference to which is the puppy that is known to be male. It is invalid to say that you can just choose one because you can't, precisely because we don't know if the Puppy Washing Man found the first one he picked up to be male or the second one he picked up to be male. Doing so would be to create extra information that is not given in the problem, which would mean that you are the only one who has been changing the problem all this time.

Another thing is that this kind of problem is what is known as a brain teaser. The wording of brain teasers is logically consistent and grammatically correct. But, they take advantage of the ambiguities of the English language to create statements that can be easily misinterpreted if one does not exercise careful reading comprehension. In fact, taking the statements of brain teasers at literal face value, as you have apparently done, will almost always lead you to exactly the wrong answer. You have to read the total context of the problem and comprehend the total action occurring in the problem.

Finally, if you really don't want to believe us, you can look the problem up on wikipedia. The wording is EXACTLY the same (http://en.wikipedia.org/wiki/Marilyn_vos_Savant [http://en.wikipedia.org/wiki/Marilyn_vos_Savant], look for the "Two Boys" problem). You can also check this link http://en.wikipedia.org/wiki/Boy_or_Girl_paradox [http://en.wikipedia.org/wiki/Boy_or_Girl_paradox], where they point out exactly the fallacies in logic that most people who choose 50% make.
 

geizr

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FrcknFrckn post=18.73797.838457 said:
Alex_P post=18.73797.838442 said:
FrcknFrckn post=18.73797.838427 said:
Alex_P post=18.73797.838416 said:
There are two dogs, Jesus and Satan.

If you ask "Is Jesus male?" and the answer is "Yes," there is a 50% chance that Satan is male.

If you ask "Is at least one of them male?" and the answer is "Well, Jesus is male," there is still only a 33% chance that Satan is male. Even though you specifically know Jesus is the male dog.

-- Alex
Actually, both those cases are 50%. In both, we end up with the same information: Jesus is male. We know nothing about Satan, so there's a 50% chance he's male or female.

The probability difference arises if you ask "Is at least one of them male?" and the answer is "Yes." In that situation, there is only a 33% chance that both Jesus and Satan is male.
No, read the second situation carefully.

The trick is that you're inviting the puppy-washer to decide which dog you're referring to, and he can always pick the more favorable answer. If Jesus were female he could've said "Yes, Satan is male" instead.

-- Alex
Ah, yeah, missed that... good point, objection retracted! :)
Actually, your original objection is correct. It is the fact that a specific one is known to be male that the 50% probability occurs. It is only if the person answers "yes" in the second case without giving ANY information to which one he is referring do you get 33%. This is the same case as the originally stated problem.

It doesn't matter that the puppy-washer decides which dog you meant to ask about. It's the fact that you now have information that specifies the gender of a particular puppy.
 

geizr

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Cheeze_Pavilion post=18.73797.838877 said:
geizr post=18.73797.838752 said:
"Is at least one a male?" she asks him. "Yes!" she informs you with a smile.
This is the first point where your logic falls off, Cheeze. The shopkeeper only asks whether at least one puppy is male, not which one. We don't know at this point if one or both puppies are male. In the case of only one being male, at this point, we don't know which one. We can not force the label on the male one to be dog1. Consider this scenario. The Puppy Washing Man picks up one puppy and looks at it and discovers it is male. At that point, he can truthfully answer the shopkeeper in the affirmative that at least one puppy is male. But, it could be that he picks up the first puppy and discovers it is female. So, he must then pick up and examine the second puppy to properly answer the shopkeeper. It is because we don't know what the Puppy Washing Man had to do to determine if there is at least one male that we get 3 total configurations possible.
No, you get two possible scenarios of two configurations:

M/? "The Puppy Washing Man picks up one puppy and looks at it and discovers it is male."

XOR

F/M "it could be that he picks up the first puppy and discovers it is female. So, he must then pick up and examine the second puppy to properly answer the shopkeeper"

You can't smush together two different, mutually exclusive scenarios each with two configurations into one, three configuration scenario.
Yes, you can, Cheeze, because you don't know which scenario has occurred. So, you must count both. It is invalid to assume that only one or the other situation has occurred. You've been constantly saying that the rest of us are wrong, but, I've seen no logic on your part to prove your point, only claims. Show us, completely, your logic for how you obtain 50% as the correct answer.
 

Alex_P

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Cheeze_Pavilion post=18.73797.838854 said:
Alex_P post=18.73797.838647 said:
Well, this one is intentionally tricky.
What's wrong with writing the possibilities like this:

Jesus/Satan
M/M
M/F

and if there's nothing wrong with writing it like that, why do you think one row is twice as likely than the other?
See what I said about conditional probabilities above...

Implicit in my problem was the idea that the only statements the puppy-washer can make are "Jesus is male," "Satan is male," or "Neither is male."

Given that Jesus is male, what can we say about each potential pair?
P ( J = F, S = F | J = M ) = 0
P ( J = F, S = M | J = M ) = 0
P ( J = M, S = F | J = M ) = 1/2
P ( J = M, S = M | J = M ) = 1/2
In other words, the conclusion you already have above, Cheeze.

However, there is another fact in play: the puppy-washer, selecting from those three possible responses, chose to tell us "Jesus is male."

So, for each of the pairs that you haven't thrown out (M/F and M/M), what is the probability that he would say that?
P ( puppy-washer says "Jesus is male" | J = M, S = F ) = 1
P ( puppy-washer says "Jesus is male" | J = M, S = M ) = 1/2

P ( puppy-washer says "Jesus is male" | J = F, S = F ) = 0
P ( puppy-washer says "Satan is male" | J = F, S = F ) = 0
P ( puppy-washer says "Neither is male" | J = F, S = F ) = 1

P ( puppy-washer says "Jesus is male" | J = F, S = M ) = 0
P ( puppy-washer says "Satan is male" | J = F, S = M ) = 1
P ( puppy-washer says "Neither is male" | J = F, S = M ) = 0

P ( puppy-washer says "Jesus is male" | J = M, S = F ) = 1
P ( puppy-washer says "Satan is male" | J = M, S = F ) = 0
P ( puppy-washer says "Neither is male" | J = M, S = F ) = 0

P ( puppy-washer says "Jesus is male" | J = M, S = M ) = 1/2
P ( puppy-washer says "Satan is male" | J = M, S = M ) = 1/2
P ( puppy-washer says "Neither is male" | J = M, S = M ) = 0

Also note that, of all the options,
P ( puppy-washer says "Neither is male" ) = 1/4
P ( puppy-washer says "Jesus is male" ) = 3/8
P ( puppy-washer says "Satan is male" ) = 3/8

We want to find P ( J = M, S = M | puppy-washer says "Jesus is male" ), right?

P ( J = M, S = M | puppy-washer says "Jesus is male" ) = P ( puppy-washer says "Jesus is male" | J = M, S = M ) * P ( J = M, S = M ) / P ( puppy-washer says "Jesus is male" ) = (1/2) * (1/4) / (3/8) = 1/3

-- Alex
 

Alex_P

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geizr post=18.73797.838889 said:
Actually, your original objection is correct. It is the fact that a specific one is known to be male that the 50% probability occurs. It is only if the person answers "yes" in the second case without giving ANY information to which one he is referring do you get 33%. This is the same case as the originally stated problem.

It doesn't matter that the puppy-washer decides which dog you meant to ask about. It's the fact that you now have information that specifies the gender of a particular puppy.
Not quite. It depends on the answer set that the puppy-washer's answer is drawn from.

If you are given "Jesus is male" vs. "Jesus is female," then "Jesus is male" gives you 50% certainty.
If you are given "Jesus is male" vs. "Satan is male" vs. "Neither is male" (you need that third one because it could be neither), then "Jesus is male" gives you 33% certainty based on the calculation I outlined above.

-- Alex
 

Alex_P

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Contemplate this problem for a minute. Not identical, but related:

You have two domino tiles.
One of them has is a null/one domino.
The other is a one/one domino.

You lay them down on the table and shuffle them around until you no longer recall which is which. They are, for all intents and purposes, random.

Now you pick one at random and look at only one side of it.

You see a one on the side you looked at.

What is the chance there is a one on the side you currently can't see?

-- Alex
 

geizr

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Cheeze_Pavilion post=18.73797.838942 said:
Ahh--my bad: I thought the scenarios were parallel; you wrote "one" in one and "first" in the other.

I would say then that you've confused the number of ways he can *learn* the sex of the puppies with the number of possible configurations of the puppies. Big difference.
No, I have not confused the number of ways to learn about the puppies with the number of configurations. I have used the fact that there are two ways to determine the sex of the puppies to realize that I have no information about which one IS the male one. This leads me to generate 3 total, unique configurations of the puppies.

Cheeze_Pavilion post=18.73797.838942 said:
As for how I obtain 50%? I say the fact that it asks us about the probability of the sex of "the other one" means we are to take the information that there is one male as being not only about the set, but about a specific puppy, the puppy that is not "the other one" so:

The one that is not the other one/"the other one"
M/M
M/F
And I am telling you that this is where your error lies. You don't know if "not the other one" means specifically dog1 or specifically dog2. This is why the case you list of M/F has a 2-fold degeneracy and must be counted twice: once for the case that dog1 is "not the other one" and once for the case that dog2 is "not the other dog". You have to do this because you don't know which one is "not the other one"(is it dog1 or dog2?), which also means you don't know which one is "the other one"(dog2 or dog1?). When you account for this degeneracy, you obtain the CORRECT answer of 33%.

To impose that "not the other one" refers to a specific dog is the logic fallacy you constantly and persistently keep making. Making such an assertion adds information to the problem that does not exist; yet, time and again, you keep making this assertion.

I have mentioned a couple times that while it is possible to do it this way, the logic is treacherous because of the need to find this degeneracy. Writing the problem out simply with the information given leads you to the 3 explicit configurations of M/M, M/F, and F/M without the need to find hidden degeneracies. From this, you calculate the correct answer of 33%. I have shown you the logic of solving this problem 2 or 3 different ways and derived the exact same answer, logically and consistently. I've even shown you, logically, why even if we take your interpretation we still obtain 33%. Yet, you still insist on adding information to the problem that does not exist. There is no specification of which dog is the "not the other one" and being the male dog; so, it is illogically to impose that "the other one" must then refer to a specific dog. To persist in this fallacy you are either being stubborn or just trying to get attention, or possibly both.
 

geizr

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Alex_P post=18.73797.838955 said:
geizr post=18.73797.838889 said:
Actually, your original objection is correct. It is the fact that a specific one is known to be male that the 50% probability occurs. It is only if the person answers "yes" in the second case without giving ANY information to which one he is referring do you get 33%. This is the same case as the originally stated problem.

It doesn't matter that the puppy-washer decides which dog you meant to ask about. It's the fact that you now have information that specifies the gender of a particular puppy.
Not quite. It depends on the answer set that the puppy-washer's answer is drawn from.

If you are given "Jesus is male" vs. "Jesus is female," then "Jesus is male" gives you 50% certainty.
If you are given "Jesus is male" vs. "Satan is male" vs. "Neither is male" (you need that third one because it could be neither), then "Jesus is male" gives you 33% certainty based on the calculation I outlined above.

-- Alex
If I recall correctly, in the second scenario you set up, you said the puppy-washer answers "Well, Jesus is male". Regardless of the intent of the person asking the question, the puppy-washer has given specific information that indicates a specific dog is male. This information has been communicated to the person asking the question, and now he becomes aware of the fact Jesus is male. Because of that specificity of knowledge, the probability of Satan being male is 50%, in that scenario. The case of neither being male is not possible because you have given this specific information that Jesus is male.
 

Alex_P

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geizr post=18.73797.839039 said:
Alex_P post=18.73797.838955 said:
geizr post=18.73797.838889 said:
Actually, your original objection is correct. It is the fact that a specific one is known to be male that the 50% probability occurs. It is only if the person answers "yes" in the second case without giving ANY information to which one he is referring do you get 33%. This is the same case as the originally stated problem.

It doesn't matter that the puppy-washer decides which dog you meant to ask about. It's the fact that you now have information that specifies the gender of a particular puppy.
Not quite. It depends on the answer set that the puppy-washer's answer is drawn from.

If you are given "Jesus is male" vs. "Jesus is female," then "Jesus is male" gives you 50% certainty.
If you are given "Jesus is male" vs. "Satan is male" vs. "Neither is male" (you need that third one because it could be neither), then "Jesus is male" gives you 33% certainty based on the calculation I outlined above.

-- Alex
If I recall correctly, in the second scenario you set up, you said the puppy-washer answers "Well, Jesus is male". Regardless of the intent of the person asking the question, the puppy-washer has given specific information that indicates a specific dog is male. This information has been communicated to the person asking the question, and now he becomes aware of the fact Jesus is male. Because of that specificity of knowledge, the probability of Satan being male is 50%, in that scenario. The case of neither being male is not possible because you have given this specific information that Jesus is male.
Ah, but the possibility space of the answers contains additional information.

Roughly put, if Jesus is the only male, then the puppy-washer will always say "Jesus is male," but if Jesus is one of two males, then the puppy-washer will only say "Jesus is male" half the time, because he could also say "Satan is male" instead.

See my Bayes' Theorem explanation in post 783.

-- Alex
 

geizr

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Alex_P post=18.73797.839056 said:
geizr post=18.73797.839039 said:
Alex_P post=18.73797.838955 said:
geizr post=18.73797.838889 said:
Actually, your original objection is correct. It is the fact that a specific one is known to be male that the 50% probability occurs. It is only if the person answers "yes" in the second case without giving ANY information to which one he is referring do you get 33%. This is the same case as the originally stated problem.

It doesn't matter that the puppy-washer decides which dog you meant to ask about. It's the fact that you now have information that specifies the gender of a particular puppy.
Not quite. It depends on the answer set that the puppy-washer's answer is drawn from.

If you are given "Jesus is male" vs. "Jesus is female," then "Jesus is male" gives you 50% certainty.
If you are given "Jesus is male" vs. "Satan is male" vs. "Neither is male" (you need that third one because it could be neither), then "Jesus is male" gives you 33% certainty based on the calculation I outlined above.

-- Alex
If I recall correctly, in the second scenario you set up, you said the puppy-washer answers "Well, Jesus is male". Regardless of the intent of the person asking the question, the puppy-washer has given specific information that indicates a specific dog is male. This information has been communicated to the person asking the question, and now he becomes aware of the fact Jesus is male. Because of that specificity of knowledge, the probability of Satan being male is 50%, in that scenario. The case of neither being male is not possible because you have given this specific information that Jesus is male.
Ah, but the possibility space of the answers contains additional information.

Roughly put, if Jesus is the only male, then the puppy-washer will always say "Jesus is male," but if Jesus is one of two males, then the puppy-washer will only say "Jesus is male" half the time, because he could also say "Satan is male" instead.

See my Bayes' Theorem explanation in post 783.

-- Alex
Okay, here is the original text of the problem you proposed:

It all depends on who identifies which dog is the "referent."

There are two dogs, Jesus and Satan.

If you ask "Is Jesus male?" and the answer is "Yes," there is a 50% chance that Satan is male.

If you ask "Is at least one of them male?" and the answer is "Well, I noticed that Jesus is male," there is still only a 33% chance that Satan is male -- even though you specifically know Jesus is the male dog.
Now, I read your Bayes' Theorem post, and I have a couple of problems with it. First, once you introduce choice or the whim of the puppy-washer, all ability to talk about probabilities reliably is lost. Second, I am not quite seeing how you obtained P( puppy-washer says "Jesus is male") = 3/8. That seems like an assertion to me, but, I am probably missing something. If I just use the sum of the two probabilities you give, then I get 1.5 for the total probability that he says "Jesus is male" at all, which can not possibly be correct. So, there must be something subtle I'm missing in what you are saying.
 

Alex_P

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geizr post=18.73797.839149 said:
Now, I read your Bayes' Theorem post, and I have a couple of problems with it. First, once you introduce choice or the whim of the puppy-washer, all ability to talk about probabilities reliably is lost. Second, I am not quite seeing how you obtained P( puppy-washer says "Jesus is male") = 3/8. That seems like an assertion to me, but, I am probably missing something. If I just use the sum of the two probabilities you give, then I get 1.5 for the total probability that he says "Jesus is male" at all, which can not possibly be correct. So, there must be something subtle I'm missing in what you are saying.
To get 1/4, 3/8, 3/8, you take the sum of P ( some result ) * P ( some answer | some result ).

So, to get P ( puppy-washer says "Jesus is male" ), I did:
P ( puppy-washer says "Jesus is male" )
= P ( puppy-washer says "Jesus is male" | J = F, S = F ) * P ( J = F, S = F )
+ P ( puppy-washer says "Jesus is male" | J = F, S = M ) * P ( J = F, S = M )
+ P ( puppy-washer says "Jesus is male" | J = M, S = F ) * P ( J = M, S = F )
+ P ( puppy-washer says "Jesus is male" | J = M, S = F ) * P ( J = M, S = M )

So, P ( puppy-washer says "Jesus is male" ) = 0*(1/4) + 0*(1/4) + 1*(1/4) + (1/2)*(1/4) = 3/8

A quick way to think about it is that if the only answers are "Jesus," "Satan," and "Neither," then the "Both" result gets split equally between "Jesus" and "Satan."

-- Alex
 

NeedAUserName

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Cheeze_Pavilion post=18.73797.839189 said:
needausername post=18.73797.839164 said:
Why have the puppies been named Jesus and Satan?
Because the fate of all the souls in the world depends on figuring out the probability that "the other one" is male, just like the card game between George Burns and George Burns in _Oh God, You Devil!_
Confused much?