This needs to be seen again and again.Slenn said:Yes, but it depends on the function given. If it's y=1/x, then you can't divide by zero because the limits coming from either side of the graph don't equal each other:
Lim
x-->0+ (1/x) = ∞
Lim
x-->0- (1/x) = -∞
However if you take y=1/(x^2), then you can take the limit because the limits are both the same. In this case dividing by zero will give you infinity. If you take calculus you'd understand this a bit better.
Lim
x-->0+ (1/(x^2)) = ∞
Lim
x-->0- (1/(x^2)) = ∞