Riddle Thread.

Recommended Videos

Redingold

AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
Mar 28, 2009
1,641
0
0
c_westerman13 said:
Redingold said:
1. You have two old-fashioned hourglasses. One contains five hours of sand, one contains eight. How would you go about timing eleven hours?

2. You have an old-fashioned pair of scales. Given that you must weigh a series of objects with integer masses between 1 and 40 grams, inclusive, what is the lowest number of weights needed to weigh any given object?
1) turn both over. when the five runs out, turn it over, once the 8 is empty, the 5 is divided into 3:2. place the 5 on its side to suspend it, run the eight fully, then use the 3 from the 5 hourglass as it finishes. 8+3=11

2)6: 1,2,4,8,16,32
You're correct on the first one, though there's a better way of doing it, where you don't have to waste time at the start, and wrong on the second one.

For the first one, run both of them, and when the five runs out, turn it over, then when the eight runs out, turn the five over again.
 

Trivun

Stabat mater dolorosa
Dec 13, 2008
9,831
0
0
Redingold said:
1. You have two old-fashioned hourglasses. One contains five hours of sand, one contains eight. How would you go about timing eleven hours?

2. You have an old-fashioned pair of scales. Given that you must weigh a series of objects with integer masses between 1 and 40 grams, inclusive, what is the lowest number of weights needed to weigh any given object?
1. You start timing them both at the same time. When the five-hour timer ends and the sand runs out, you know that there are three hours left on the eight-hour timer. You then simply measure the eleven hours from that point, flipping the eight-hour timer when it finishes.

To put it another way, 8-5=3. So there are 3 hours left on the 8-hour timer. Then you simply measure 8+3 which equals 11.

2. Can't be bothered to work this out as I don't have the time, however I could do if given time as I study maths. Ah well, someone else is bound to post it anyway...
 

c_westerman13

New member
Mar 29, 2011
329
0
0
i think its safe to say my riddle has been solved!!

i lost my hat this morning. after about an hour of searching, i found it. what was the first thing i did once i found it?
 

kane.malakos

New member
Jan 7, 2011
344
0
0
norwegian-guy said:
What happens when an unstopable force meets an
It cannot be heared, it cannot be felt.
It cannot be seen, it cannot be smeled.
It lies behind the stars and under hills,
and empty holes it fills.
Comes first, follows after.
Ends life, kills laughter.
Of what do I speak?
The dark?
 

norwegian-guy

New member
Jan 17, 2011
266
0
0
kane.malakos said:
norwegian-guy said:
What happens when an unstopable force meets an
It cannot be heared, it cannot be felt.
It cannot be seen, it cannot be smeled.
It lies behind the stars and under hills,
and empty holes it fills.
Comes first, follows after.
Ends life, kills laughter.
Of what do I speak?
The dark?
Indeed.
 

c_westerman13

New member
Mar 29, 2011
329
0
0
Redingold said:
c_westerman13 said:
Redingold said:
1. You have two old-fashioned hourglasses. One contains five hours of sand, one contains eight. How would you go about timing eleven hours?

2. You have an old-fashioned pair of scales. Given that you must weigh a series of objects with integer masses between 1 and 40 grams, inclusive, what is the lowest number of weights needed to weigh any given object?
1) turn both over. when the five runs out, turn it over, once the 8 is empty, the 5 is divided into 3:2. place the 5 on its side to suspend it, run the eight fully, then use the 3 from the 5 hourglass as it finishes. 8+3=11

2)6: 1,2,4,8,16,32
You're correct on the first one, though there's a better way of doing it, where you don't have to waste time at the start, and wrong on the second one.

For the first one, run both of them, and when the five runs out, turn it over, then when the eight runs out, turn the five over again.
wrong on the second one. hmmmm...
you've got me there, what is it?
 

Doive

New member
Nov 6, 2010
165
0
0
c_westerman13 said:
i think its safe to say my riddle has been solved!!

i lost my hat this morning. after about an hour of searching, i found it. what was the first thing i did once i found it?
Took it off?
 

Stix700

New member
Jan 14, 2011
6
0
0
c_westerman13 said:
i think its safe to say my riddle has been solved!!

i lost my hat this morning. after about an hour of searching, i found it. what was the first thing i did once i found it?
Stop looking.
 

Redingold

AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
Mar 28, 2009
1,641
0
0
c_westerman13 said:
Redingold said:
c_westerman13 said:
Redingold said:
1. You have two old-fashioned hourglasses. One contains five hours of sand, one contains eight. How would you go about timing eleven hours?

2. You have an old-fashioned pair of scales. Given that you must weigh a series of objects with integer masses between 1 and 40 grams, inclusive, what is the lowest number of weights needed to weigh any given object?
1) turn both over. when the five runs out, turn it over, once the 8 is empty, the 5 is divided into 3:2. place the 5 on its side to suspend it, run the eight fully, then use the 3 from the 5 hourglass as it finishes. 8+3=11

2)6: 1,2,4,8,16,32
You're correct on the first one, though there's a better way of doing it, where you don't have to waste time at the start, and wrong on the second one.

For the first one, run both of them, and when the five runs out, turn it over, then when the eight runs out, turn the five over again.
wrong on the second one. hmmmm...
you've got me there, what is it?
You can do it with 4: 1, 3, 9 and 27.

You can place weights on either side of a set of scales. So to measure, say, 5, you'd put a 9 on one side and a 3 and a 1 on the other.
 

norwegian-guy

New member
Jan 17, 2011
266
0
0
Professor Cubbage said:
norwegian-guy said:
What happens when an unstopable force meets an immovable object?
Both things cannot exist as they contradict each other.
Yes, yes paradox and all that, but superman solved it. I'm serious, there's a superman-comic where he gives the best answer to the riddle I have ever heared.
 

Gxas

New member
Sep 4, 2008
3,187
0
0
c_westerman13 said:
Gxas said:
hittite said:
Gxas said:
A man leaps off of the roof of an eleven story building. He takes a running start and when he leaves the roof, he is traveling at 3.2m/s.

How long does it take him to reach the ground?
The rest of his life.
DING DING!

We gave that to my Physics teacher in high school. He took the whole hour and a half of class writing it out. Bell rang, we told him the answer. Free day of class!
that isn't a specific length of time.

EDIT: specific length of time with a known magnitude.
It doesn't ask for that. Just asks how long.
 

c_westerman13

New member
Mar 29, 2011
329
0
0
The Night Shade said:
What's the thing that Always goes up but never down?
the amount of time (in arbitrary units of time) which has elapsed since event x

norwegian-guy said:
What happens when an unstopable force meets an immovable object?
the resulting collision causes a black hole, which sucks in the unstoppable force, but cannot (obviously) move the immovable object. ergo the immoveable object wins.

Doive said:
c_westerman13 said:
i think its safe to say my riddle has been solved!!

i lost my hat this morning. after about an hour of searching, i found it. what was the first thing i did once i found it?
Took it off?
very humourous, but even assuming i found it on my head, still incorrect.
 

kane.malakos

New member
Jan 7, 2011
344
0
0
norwegian-guy said:
Professor Cubbage said:
norwegian-guy said:
What happens when an unstopable force meets an immovable object?
Both things cannot exist as they contradict each other.
Yes, yes paradox and all that, but superman solved it. I'm serious, there's a superman-comic where he gives the best answer to the riddle I have ever heared.
One reply I've heard is just that the unstoppable force stops and the immovable object moves...
 

Rhaff

New member
Jan 30, 2011
187
0
0
2 fathers and 2 sons were out hunting one day. By the end of the day, they had each shot and killed one duck, but they only bring home 3 ducks. How is this possible?
 

c_westerman13

New member
Mar 29, 2011
329
0
0
Redingold said:
c_westerman13 said:
Redingold said:
c_westerman13 said:
Redingold said:
1. You have two old-fashioned hourglasses. One contains five hours of sand, one contains eight. How would you go about timing eleven hours?

2. You have an old-fashioned pair of scales. Given that you must weigh a series of objects with integer masses between 1 and 40 grams, inclusive, what is the lowest number of weights needed to weigh any given object?
1) turn both over. when the five runs out, turn it over, once the 8 is empty, the 5 is divided into 3:2. place the 5 on its side to suspend it, run the eight fully, then use the 3 from the 5 hourglass as it finishes. 8+3=11

2)6: 1,2,4,8,16,32
You're correct on the first one, though there's a better way of doing it, where you don't have to waste time at the start, and wrong on the second one.

For the first one, run both of them, and when the five runs out, turn it over, then when the eight runs out, turn the five over again.
wrong on the second one. hmmmm...
you've got me there, what is it?
You can do it with 4: 1, 3, 9 and 27.

You can place weights on either side of a set of scales. So to measure, say, 5, you'd put a 9 on one side and a 3 and a 1 on the other.
oh, i never even condsidered using both sides! dammit! =[
 

kane.malakos

New member
Jan 7, 2011
344
0
0
Rhaff said:
He didn't ask for a specific value, just how long..

OT: 2 fathers and 2 sons were out hunting one day. By the end of the day, they had each shot and killed one duck, but they only bring home 3 ducks. How is this possible?
It's a grandfather, a father, and a son.
 

c_westerman13

New member
Mar 29, 2011
329
0
0
Rhaff said:
He didn't ask for a specific value, just how long..

OT: 2 fathers and 2 sons were out hunting one day. By the end of the day, they had each shot and killed one duck, but they only bring home 3 ducks. How is this possible?
grandfather (f), father(f,s), and son (s)