There needs to be something added if we want the true form of the riddle, since parts have been missed out.
Answer this question, who tells you that one's a liar the other's truthful? Is it a neutral third party (like, a sign or something), or the guards themselves?
Answer this question, who tells you that one's a liar the other's truthful? Is it a neutral third party (like, a sign or something), or the guards themselves?
I don't understand that part about the 5th pirate so I'll wait for the final answer, in my situation the 2nd pirate wouldn't need to accept because he'll be overruled. And the 2nd pirate was never going to get 99 gold, because there would always be enough people to overrule him and he'll be killed. He'll disagree on the first pirate's division, as will others, so the first pirate will be killed, then on his turn he'll try to give himself 99 gold and the other 3 will overrule and kill him. If the 2nd pirate won't agree except for 99 gold then he'll get bugger-all except a knife in the back.Cpt. Red said:Wrong. The fifth pirate can never expect to get more then one gold. Therefore your solution is not optimal for the the first pirate.Amethyst Wind said:The first pirate gives the 4th and 5th pirates 50 gold each.
The way that the question is worded makes it nigh on impossible for the first pirate to get any gold, so his only goal is to escape with his life. The best way for him to do that is to get a majority agreement vote. Because the last two will both get half even if they disagree, their maximum possible gold is 50 coins apiece. Give them this at the beginning and 3 of the 5 are happy, and nobody dies.
You could give the 2nd and 3rd pirates 50 gold apiece, so there'd still be a 50/50 split (2 for, 2 against) but then you'd have to kill the first pirate.
Also the second pirate will never accept unless he gets 99 or more.