provided that the death star was close enough for its mass to affect the tides, then yes it would have an effect. but remember the force of gravity between two objects decreases over the square of the distance between the two objects, so depending on the death star's mass it might have to be quite close (relatively speaking) to have noticeable effects on the tides.Lord Garnaat said:Alright all you science-inclined Escapists, I have a question that I've been rattling around in my mind for a while.
In the Star Wars movies the Death Star is supposed to be big. Really, really big. Big enough that it could be mistaken for a moon when it's near a planet. But when I thought about this, a rather interesting question sprang to mind: if the Death Star is large enough to be mistaken for a moon, would it affect the tides of a planet when it came close to it? I realize that tides are normally caused by the moon, so would the addition of a moon-sized object so close to a planet cause the normal patterns to get screwed up? Or would it be either too small or too far away to make a difference?
the bigger question would be, would the death star survive the tidal forces subjected to it by being that close to an object so much more massive than it is (i.e. roche limit)? i doubt it.
all that being said, given that the death star is designed to show and blow up the planet in question, the death star wins by default.
edit: changed waves to tides and clarified a thing or two.