Poll: Solve a simple math problem

[Maze1125]

Well i'm not sure but my maths text book says 1/0 is infinity so no ofense but i'll trust that over you.

Are you sure it doesn't just say that the limit of 1/x as x->0 is infinity? Infinity is a tricky concept...

Pretty sure as some questions in the book required you to use 'infinity = 1/0' in order to get to the correct answer.

Example please?

Riemann Sphere [http://en.wikipedia.org/wiki/Riemann_sphere]

 

[Vykrel]

this thread shows that 2/3 of people havent learned the order of operations.

 

[madwarper]

this thread shows that 2/3 of people havent learned the order of operations.

2/3?

Considering just under 50% (49.8 currently) got the answer correct, you might want to revise your statement...

 

[Purple Shrimp]

Something here is being multiplied by zero, which is equal to dividing by zero. Answer is zero.

First, your tidbit about multiplying by zero may be correct

it isn't

 

[madwarper]

Something here is being multiplied by zero, which is equal to dividing by zero. Answer is zero.

First, your tidbit about multiplying by zero may be correct

it isn't

It is. The "1*0" is 0.

That fact doesn't change the fact that the equation then boils down to 10 -1 +5 +0.

 

[Purple Shrimp]

Something here is being multiplied by zero, which is equal to dividing by zero. Answer is zero.

First, your tidbit about multiplying by zero may be correct

it isn't

It is. The "1*0" is 0.

That fact doesn't change the fact that the equation then boils down to 10 -1 +5 +0.

you underlined "which is equal to dividing by zero", which isn't true

 

[madwarper]

you underlined "which is equal to dividing by zero", which isn't true

You're right, I did. And, you're right that it's not true.

However, did you read my ENTIRE post? You know, including the second line, which was color coded with the underlined part?

which is equal to dividing by zero.

Secondly, and more importantly, anything divided by 0 is undefined, it's NOT 0.

 

[Pat8u]

The answer is minus infinity.
(1+1+1+1+1+1+1+1+1+1)-(1+1+1+1+1+1+(1/0))
=10-(6+infinity)
=10-infinity
=-infinity
If the end was 1*0= then the answer would be 4 as adding brackets the sum equates to
(1+1+1+1+1+1+1+1+1+1)-(1+1+1+1+1+1+(1*0))
=10-(6+0)
=4

*slaps* X/0 IS UNDEFINED!

The (new) answer is 14.

One of the deffinitions of infinity is 1/0 so in this case i'm right.

It's not. You're wrong.

Infinity multiplied by 0 is still 0.

Well i'm not sure but my maths text book says 1/0 is infinity so no ofense but i'll trust that over you.

Then your textbook is wrong. Do I really need to prove this to you?

Really?

*sigh*

So your question is what does 1/0 equal, right? Let's rewrite that as an equation, so

1/0 = X

. Using basic Key Stage 1 maths, this means that

X*0 = 1

. Any number multiplied by 0 equals 0 - this doesn't need maths, that's just logic. And that includes infinity - it doesn't matter what X is, there are no X'es. Therefore

X*0

ALWAYS equals 0, so the question is fundamentally flawed.

Writing

X/0 = 1

is akin to writing

2 + 2 = 5

. YOU. ARE. WRONG.

1+1+1+1+1+1+1+1+1+1-1+1+1+1+1+1+1X0=14
\ / \ / \ / \ / \ / \ / \ / \ / \ /
2 2 2 2 2 0 2 2 0
\ / \ / \ / \ /
4 4 2 4
\ / \ /
8 6
\ /
14
Order of Operations dictates that it goes parentheses, multiplication/division, then add/subtraction. There are no parentheses, so you first multiply the 1X0=0. After that, you just add/subtract the 1 and 0. also the the person who said this:
(1+1+1+1+1+1+1+1+1+1)-(1+1+1+1+1+1+1X0)=/=1+1+1+1+1+1+1+1+1+1-1+1+1+1+1+1+1X0
because1+1+1+1+1+1+1+1+1+1)-(1+1+1+1+1+1+1X0)=1+1+1+1+1+1+1+1+1+1-1-1-1-1-1-1-1X0
also 1/0 is infinity. You add anything to infinity, it is still infinity.

Not you too...

the wiki had some information on this
The set is the Riemann sphere, which is of major importance in complex analysis. Here too is an unsigned infinity ? or, as it is often called in this context, the point at infinity. This set is analogous to the real projective line, except that it is based on the field of complex numbers. In the Riemann sphere 1/0=infintiy but 0/0 is undefined
EDIT: THE WIKI hadd symbols in some places but all relative information is there also I don't know that much about maths to get into that debate so don't fight with me fight between yourselves

OT 14 easy

OT:

 

[Purple Shrimp]

you underlined "which is equal to dividing by zero", which isn't true

You're right, I did. And, you're right that it's not true.

However, did you read my ENTIRE post? You know, including the second line, which was color coded with the underlined part?

which is equal to dividing by zero.

Secondly, and more importantly, anything divided by 0 is undefined, it's NOT 0.

i assumed that "Something here is being multiplied by zero" was too ridiculously obvious to even comment on, but i suppose since your entire goal within this thread seems to be to repeat obvious things I shouldn't have made that assumption

 

[Sizzle Montyjing]

At the end there, is it being multiplied by zero?
Becuase if it is i believe that anything multiplied by zero, is zero.
So zero.

 

[madwarper]

i assumed that "Something here is being multiplied by zero" was too ridiculously obvious to even comment on, but i suppose since your entire goal within this thread seems to be to repeat obvious things I shouldn't have made that assumption

And, I assumed that people weren't going to quote me out of context.

It appears we've both been mistaken.

 

[Neonit]

good god.... i saw it on facebook fails and though "well, ok, its facebook -.-'"
but here? cmon guys.... 32% voted on 0?!

well, i dont know what to say..... its 14 btw.....

 

[madwarper]

Look's like I shall disappoint Purple Shrimp yet again, by pointing out something "too ridiculously obvious".

At the end there, is it being multiplied by zero?
Becuase if it is i believe that anything multiplied by zero, is zero.
So zero.

Yes, there is something being multiplied by 0. But, what is "it", that's being multiplied?

If you're thinking that it's the sum of the previous numbers, you're mistaken.

In order of operations, multiplication happens before addition/subtraction. The sole 1 at the end become 0. And, then you take the sum of the rest of the numbers as normal.

 

[imnot]

No math can go die in a hole!
Besides im incredibly lazy
my guess is 56

 

[cahtush]

its 14,but if it where (1+1+1...+1)*0 it would be 0

 

[Sizzle Montyjing]

Look's like I shall disappoint Purple Shrimp yet again, by pointing out something "too ridiculously obvious".

At the end there, is it being multiplied by zero?
Becuase if it is i believe that anything multiplied by zero, is zero.
So zero.

Yes, there is something being multiplied by 0. But, what is "it", that's being multiplied?

If you're thinking that it's the sum of the previous numbers, you're mistaken.

In order of operations, multiplication happens before addition/subtraction. The sole 1 at the end become 0. And, then you take the sum of the rest of the numbers as normal.

I'm pretty sure that, if being multiplied by zero is at the last stage in the sum, then it is indeed zero, becuase zero lots of anything is zero.
Or am i missing something?

 

[The Cheezy One]

My problem is that it is maths, not math. You wouldn't say 'I'm going to university to study mathematic'. Let the 19th letter of the alphabet back into your life.

OT: Yeah, I think you got it pretty much right in your solution. Multiplication comes first, and then addition and subtraction, in either order.

 

[bad rider]

Gah, I counted one too many ones. Did the bidmas and subtraction bit though.

 

[madwarper]

Look's like I shall disappoint Purple Shrimp yet again, by pointing out something "too ridiculously obvious".

At the end there, is it being multiplied by zero?
Becuase if it is i believe that anything multiplied by zero, is zero.
So zero.

Yes, there is something being multiplied by 0. But, what is "it", that's being multiplied?

If you're thinking that it's the sum of the previous numbers, you're mistaken.

In order of operations, multiplication happens before addition/subtraction. The sole 1 at the end become 0. And, then you take the sum of the rest of the numbers as normal.

I'm pretty sure that, if being multiplied by zero is at the last stage in the sum, then it is indeed zero, becuase zero lots of anything is zero.
Or am i missing something?

Yes.

Order of operations; [1] Parentheses [2] Exponents [3] Multiplications/Divisions [4] Addition/Subtraction

#1: 1+1+1+1+1+1+1+1+1+1-1+1+1+1+1+1+1*0 [No parentheses]
#2: 1+1+1+1+1+1+1+1+1+1-1+1+1+1+1+1+1*0 [No exponents]
#3: 1+1+1+1+1+1+1+1+1+1-1+1+1+1+1+1+0 [Multiplication 1*0=0]
#4: 14 [Addition/Subtraction 10 -1 +5 +0 = 14]