Good luck getting it back from him.TiloXofXTanto said:I'm offended, I hate that guy. Stole the equivalent of 20 bucks from me one time, told me to turn the other cheek. Got nicer later though, but I still don't trust him.Da Chi said:You're Jesus aren't you?
If Thor's hammer's weight is incomprehensible, then it is immeasurable, and since having infinite weight is impossible, it must have an imaginary weight. Thor's hammer has negative weight, in being the square root of a negative number in weight and can therefore be picked up by dust.Da Chi said:Oh! and Thor's hammer (couldn't be arsed to look up the spelling at the moment) is a weapon of such power that it's weight is incomprehensible.
How is it that Thor can lift it?
That is such a stupid question... Just like most of the so called "great" philosophical questions of all time it is merely a question of definitions of words not true intelligence. When you think about it the question depends entirely on how you define sound. This is the first definition found on google (aka. The one most used by google users as that is how google works) and no people who use google doesn't cover everyone in the world but it is the largest sample space I can get any time soon.Mr Thin said:Actually it doesn't.AvsJoe said:Yes. The laws of physics and everything we know about the origin and properties of sound dictate that it does every time. Besides, forest critters hear the crash; if we could find a way to communicate with them, they would describe the sounds of falling trees that didn't get heard by humans.StellarViking said:Here's one I've only ever gotten one satisfactory answer to:
If a tree falls in the forest and nobody's around to hear it, does it make a sound?
http://www.wolframalpha.com/input/?...y+is+around+to+hear+it,+does+it+make+a+sound?
And if you take the question seriously, I think you have to assume there is no living thing nearby, not just no humans.
OT: What does it mean to be Australian?
Looks like it already had the door slammed in its face a few times.Skorpyo said:Open door, walk in, see this:
![]()
What do?
"Sound is a mechanical wave that is an oscillation of pressure transmitted through a solid, liquid, or gas, composed of frequencies within the range of hearing and of a level sufficiently strong to be heard, or the sensation stimulated in organs of hearing by such vibrations" by wikipedia.TiloXofXTanto said:The tree will not make a sound unless an animal with working ears is around to convert the vibrations in the air into what is properly determined to be "sound".StellarViking said:Here's one I've only ever gotten one satisfactory answer to:
If a tree falls in the forest and nobody's around to hear it, does it make a sound?
It isn't sound until it enters an ear and is converted into such an experience.
Depends on what compiler you are using. Kekeke.hyker said:is 28/2(9+3)=2 or 288?
best I could come up with
Wrong. It will reach the edge. See, after 1 year it will have travelled 1/1000 of the total distance. After two years, it will have travelled 1/1000 + 1/2000 of the distance. After three years, it will have travelled 1/1000 + 1/2000 + 1/3000. After n years, it will have travelled 1/1000 * H[sub]n[/sub], where H[sub]n[/sub] is the nth harmonic number. So, all we have to do is find the first harmonic number greater than 1000, so 1/1000 * H[sub]n[/sub] > 1. Harmonic numbers are, especially for large values of n, approximately equal to lnTiloXofXTanto said:sigh, no, it's one of those exponential decay things (with any luck) and will infinitely approach zero, only to never actually reach it.Redingold said:Now try answering it properly, with maths.TiloXofXTanto said:The space ship will not reach the edge until the edge hits the edge of an adjacent universe and begins contracting, at which point it will hit the ship in 4.83 seconds (roughly).Redingold said:One more question, then I'm outta here.TiloXofXTanto said:ayup, because the tree is able to perceive itself falling, and surrounding trees are able to perceive it as well, it invariably passes through all points needed to count as falling.Redingold said:if a tree falls in the forest and no-one is around to see it fall, does it actually fall?TiloXofXTanto said:Depends, original rule set or Flentillian rule set.Redingold said:Do all non-trivial zeros of the Riemann zeta function have a real part of 1/2?
Because the answer is either yes or Neckties.
I have a spaceship. It travels at lightspeed. I am in a universe that is 1000 lightyears across. Now, it would take me 1000 years to reach the edge of this universe. Except, this universe is expanding. Every year, it instantaneously increases its radius by 1000 lightyears. Now, it might seem that the ship never makes it to the edge, because the edge recedes faster than it can approach, but when the universe expands, everything in it is moved proportionally closer to the edge. To get my point across, after one year of travel the ship has 999 lightyears to go. The universe then expands by 1000 lightyears, doubling it's radius. So the ship is now 2 lightyears from the centre, and has 1998 to go. After another year, it is 3 lightyears from the centre, and has 1995 to go. The universe then expands by 1000 lightyears, multiplying its radius by 1.5. The ship is now 4.5 lightyears away from the centre, and has 2995.5 to go.
Will it ever reach the edge of the universe? If so, how long will this take?
That will all add up to 47 years 2 months 4 days 6 hours 47 minutes (cool right) and 4.83 seconds.
Neither. It's 168.hyker said:is 28/2(9+3)=2 or 288?
best I could come up with